Hard references are smart--they keep track of reference counts for you, automatically freeing the thing referred to when its reference count goes to zero. (Note: The reference counts for values in self-referential or cyclic data structures may not go to zero without a little help; see Two-Phased Garbage Collection for a detailed explanation. If that thing happens to be an object, the object is destructed. See the perlobj manpage for more about objects. (In a sense, everything in Perl is an object, but we usually reserve the word for references to objects that have been officially ``blessed'' into a class package.)
A symbolic reference contains the name of a variable, just as a symbolic link in the filesystem contains merely the name of a file. The *glob notation is a kind of symbolic reference. Hard references are more like hard links in the file system: merely another way at getting at the same underlying object, irrespective of its name.
``Hard'' references are easy to use in Perl. There is just one overriding principle: Perl does no implicit referencing or dereferencing. When a scalar is holding a reference, it always behaves as a scalar. It doesn't magically start being an array or a hash unless you tell it so explicitly by dereferencing it.
References can be constructed several ways.
$scalarref = \$foo; $arrayref = \@ARGV; $hashref = \%ENV; $coderef = \&handler; $globref = \*foo;
It isn't possible to create a true reference to an IO handle (filehandle or dirhandle) using the backslash operator. See the explanation of the *foo{THING} syntax below. (However, you're apt to find Perl code out there using globrefs as though they were IO handles, which is grandfathered into continued functioning.)
$arrayref = [1, 2, ['a', 'b', 'c']];
Here we've constructed a reference to an anonymous array of three elements
whose final element is itself reference to another anonymous array of three
elements. (The multidimensional syntax described later can be used to
access this. For example, after the above, $arrayref->[2][1]
would have the value ``b''.)
Note that taking a reference to an enumerated list is not the same as using square brackets--instead it's the same as creating a list of references!
@list = (\$a, \@b, \%c); @list = \($a, @b, %c); # same thing!
As a special case, \
returns a list of references to the contents of @foo
, not a reference to @foo
itself. Likewise for %foo
.
$hashref = { 'Adam' => 'Eve', 'Clyde' => 'Bonnie', };
Anonymous hash and array constructors can be intermixed freely to produce
as complicated a structure as you want. The multidimensional syntax
described below works for these too. The values above are literals, but
variables and expressions would work just as well, because assignment
operators in Perl (even within local
or my)
are
executable statements, not compile-time declarations.
Because curly brackets (braces) are used for several other things including
BLOCKs, you may occasionally have to disambiguate braces at the beginning
of a statement by putting a +
or a return in front so that Perl realizes the opening brace isn't starting a
BLOCK. The economy and mnemonic value of using curlies
is deemed worth this occasional extra hassle.
For example, if you wanted a function to make a new hash and return a reference to it, you have these options:
sub hashem { { @_ } } # silently wrong sub hashem { +{ @_ } } # ok sub hashem { return { @_ } } # ok
$coderef = sub { print "Boink!\n" };
Note the presence of the semicolon. Except for the fact that the code
inside isn't executed immediately, a sub {} is not so much a declaration as it is an operator, like do{} or eval{}. (However, no matter how many times you execute that line (unless you're
in an
eval), $coderef
will still have a reference to the SAME
anonymous subroutine.)
Anonymous subroutines act as closures with respect to my
variables, that is, variables visible lexically within the current scope.
Closure is a notion out of the Lisp world that says if you define an
anonymous function in a particular lexical context, it pretends to run in
that context even when it's called outside of the context.
In human terms, it's a funny way of passing arguments to a subroutine when you define it as well as when you call it. It's useful for setting up little bits of code to run later, such as callbacks. You can even do object-oriented stuff with it, though Perl provides a different mechanism to do that already--see the perlobj manpage.
You can also think of closure as a way to write a subroutine template without using eval. (In fact, in version 5.000, eval was the only way to get closures. You may wish to use ``require 5.001'' if you use closures.)
Here's a small example of how closures works:
sub newprint { my $x = shift; return sub { my $y = shift; print "$x, $y!\n"; }; } $h = newprint("Howdy"); $g = newprint("Greetings");
# Time passes...
&$h("world"); &$g("earthlings");
This prints
Howdy, world! Greetings, earthlings!
Note particularly that $x
continues to refer to the value
passed into newprint
despite the fact that the ``my $x'' has seemingly gone out of scope by the time the
anonymous subroutine runs. That's what closure is all about.
This applies to only lexical variables, by the way. Dynamic variables continue to work as they have always worked. Closure is not something that most Perl programmers need trouble themselves about to begin with.
new,
but don't have to be:
$objref = new Doggie (Tail => 'short', Ears => 'long');
*foo
(which is the symbol table entry which holds everything known as foo).
$scalarref = *foo{SCALAR}; $arrayref = *ARGV{ARRAY}; $hashref = *ENV{HASH}; $coderef = *handler{CODE}; $ioref = *STDIN{IO}; $globref = *foo{GLOB};
All of these are self-explanatory except for *foo{IO}. It returns the IO handle, used for file handles (open), sockets (socket and socketpair), and directory handles (opendir). For compatibility with previous versions of Perl, *foo{FILEHANDLE} is a synonym for *foo{IO}.
*foo{THING} returns undef if that particular
THING hasn't been used yet, except in the case of
scalars. *foo{SCALAR} returns a reference to an anonymous scalar if
$foo
hasn't been used yet. This might change in a future
release.
The use of *foo{IO} is the best way to pass bareword filehandles into or out of subroutines, or to store them in larger data structures.
splutter(*STDOUT{IO}); sub splutter { my $fh = shift; print $fh "her um well a hmmm\n"; }
$rec = get_rec(*STDIN{IO}); sub get_rec { my $fh = shift; return scalar <$fh>; }
Beware, though, that you can't do this with a routine which is going to open the filehandle for you, because *HANDLE{IO} will be undef if HANDLE hasn't been used yet. Use \*HANDLE for that sort of thing instead.
Using \*HANDLE (or *HANDLE) is another way to use and store non-bareword filehandles (before perl version 5.002 it was the only way). The two methods are largely interchangeable, you can do
splutter(\*STDOUT); $rec = get_rec(\*STDIN);
with the above subroutine definitions.
$bar = $$scalarref; push(@$arrayref, $filename); $$arrayref[0] = "January"; $$hashref{"KEY"} = "VALUE"; &$coderef(1,2,3); print $globref "output\n";
It's important to understand that we are specifically NOT dereferencing
$arrayref[0]
or $hashref{"KEY"}
there. The dereference of the scalar variable happens BEFORE it does any key lookups. Anything more complicated than a simple scalar
variable must use methods 2 or 3 below. However, a ``simple scalar''
includes an identifier that itself uses method 1 recursively. Therefore,
the following prints ``howdy''.
$refrefref = \\\"howdy"; print $$$$refrefref;
$bar = ${$scalarref}; push(@{$arrayref}, $filename); ${$arrayref}[0] = "January"; ${$hashref}{"KEY"} = "VALUE"; &{$coderef}(1,2,3); $globref->print("output\n"); # iff IO::Handle is loaded
Admittedly, it's a little silly to use the curlies in this case, but the BLOCK can contain any arbitrary expression, in particular, subscripted expressions:
&{ $dispatch{$index} }(1,2,3); # call correct routine
Because of being able to omit the curlies for the simple case of $$x
, people often make the mistake of viewing the dereferencing symbols as
proper operators, and wonder about their precedence. If they were, though,
you could use parentheses instead of braces. That's not the case. Consider
the difference below; case 0 is a short-hand version of case 1,
NOT case 2:
$$hashref{"KEY"} = "VALUE"; # CASE 0 ${$hashref}{"KEY"} = "VALUE"; # CASE 1 ${$hashref{"KEY"}} = "VALUE"; # CASE 2 ${$hashref->{"KEY"}} = "VALUE"; # CASE 3
Case 2 is also deceptive in that you're accessing a variable called
%hashref, not dereferencing through $hashref
to the hash it's
presumably referencing. That would be case 3.
$arrayref->[0] = "January"; $hashref->{"KEY"} = "VALUE";
The left side of the array can be any expression returning a reference,
including a previous dereference. Note that $array[$x]
is NOT the same thing as $array->[$x]
here:
$array[$x]->{"foo"}->[0] = "January";
This is one of the cases we mentioned earlier in which references could
spring into existence when in an lvalue context. Before this statement, $array[$x]
may have been undefined. If so, it's automatically defined with a hash
reference so that we can look up
{"foo"}
in it. Likewise $array[$x]->{"foo"}
will automatically get defined with an array reference so that we can look
up [0]
in it.
One more thing here. The arrow is optional BETWEEN brackets subscripts, so you can shrink the above down to
$array[$x]{"foo"}[0] = "January";
Which, in the degenerate case of using only ordinary arrays, gives you multidimensional arrays just like C's:
$score[$x][$y][$z] += 42;
Well, okay, not entirely like C's arrays, actually. C doesn't know how to grow its arrays on demand. Perl does.
ref
operator may be used to determine what type of thing
the reference is pointing to. See the perlfunc manpage.
The bless
operator may be used to associate a reference with a
package functioning as an object class. See the perlobj manpage.
A typeglob may be dereferenced the same way a
reference can, because the dereference syntax always indicates the kind of
reference desired. So ${*foo}
and ${\$foo}
both indicate the same scalar variable.
Here's a trick for interpolating a subroutine call into a string:
print "My sub returned @{[mysub(1,2,3)]} that time.\n";
The way it works is that when the @{...}
is seen in the double-quoted string, it's evaluated as a block. The block
creates a reference to an anonymous array containing the results of the
call to mysub
. So the whole block returns a reference to an array, which is then
dereferenced by @{...}
and stuck into the double-quoted string. This chicanery is also useful for
arbitrary expressions:
print "That yields @{[$n + 5]} widgets\n";
People frequently expect it to work like this. So it does.
$name = "foo"; $$name = 1; # Sets $foo ${$name} = 2; # Sets $foo ${$name x 2} = 3; # Sets $foofoo $name->[0] = 4; # Sets $foo[0] @$name = (); # Clears @foo &$name(); # Calls &foo() (as in Perl 4) $pack = "THAT"; ${"${pack}::$name"} = 5; # Sets $THAT::foo without eval
This is very powerful, and slightly dangerous, in that it's possible to intend (with the utmost sincerity) to use a hard reference, and accidentally use a symbolic reference instead. To protect against that, you can say
use strict 'refs';
and then only hard references will be allowed for the rest of the enclosing block. An inner block may countermand that with
no strict 'refs';
Only package variables are visible to symbolic references. Lexical
variables (declared with my)
aren't in a symbol table, and
thus are invisible to this mechanism. For example:
local($value) = 10; $ref = \$value; { my $value = 20; print $$ref; }
This will still print 10, not 20. Remember that local
affects
package variables, which are all ``global'' to the package.
$push = "pop on "; print "${push}over";
has always meant to print ``pop on over'', despite the fact that push is a reserved word. This has been generalized to work the same outside of quotes, so that
print ${push} . "over";
and even
print ${ push } . "over";
will have the same effect. (This would have been a syntax error in Perl 5.000, though Perl 4 allowed it in the spaceless form.) Note that this construct is not considered to be a symbolic reference when you're using strict refs:
use strict 'refs'; ${ bareword }; # Okay, means $bareword. ${ "bareword" }; # Error, symbolic reference.
Similarly, because of all the subscripting that is done using single words, we've applied the same rule to any bareword that is used for subscripting a hash. So now, instead of writing
$array{ "aaa" }{ "bbb" }{ "ccc" }
you can write just
$array{ aaa }{ bbb }{ ccc }
and not worry about whether the subscripts are reserved words. In the rare event that you do wish to do something like
$array{ shift }
you can force interpretation as a reserved word by adding anything that makes it more than a bareword:
$array{ shift() } $array{ +shift } $array{ shift @_ }
The -w switch will warn you if it interprets a reserved word as a string. But it will no longer warn you about using lowercase words, because the string is effectively quoted.
$x{ \$a } = $a;
If you try to dereference the key, it won't do a hard dereference, and you won't accomplish what you're attempting. You might want to do something more like
$r = \@a; $x{ $r } = $r;
And then at least you can use the values,
which will be real
refs, instead of the keys,
which won't.
See also the perldsc manpage and the perllol manpage for how to use references to create complex data structures, and the perlobj manpage for how to use them to create objects.